$\frac{7}{18}+\frac{11}{24}+\frac{5}{18}+\frac{13}{24}=(\frac{7}{18}+\frac{5}{18})+(\frac{11}{24}+\frac{13}{24})=\frac{12}{18}+\frac{24}{24}=\frac{2}{3}+1=1\frac{2}{3}$

$\frac{11}{50}+\frac{8}{15}+\frac{2}{15}+\frac{14}{50}=(\frac{11}{50}+\frac{14}{50})+(\frac{8}{15}+\frac{2}{15})=\frac{25}{50}+\frac{10}{15}={\frac{1}{2}}^{/3}+{\frac{2}{3}}^{/2}=\frac{3}{6}+\frac{4}{6}=\frac{7}{6}=1\frac{1}{6}$

$1\frac{3}{32}+3\frac{7}{72}+2\frac{5}{32}+4\frac{1}{36}=(1\frac{3}{32}+2\frac{5}{32})+(3\frac{7}{72}+4{\frac{1}{36}}^{/2})=3\frac{8}{32}+(3\frac{7}{72}+4\frac{2}{72})=3\frac{1}{4}+7\frac{9}{72}=3{\frac{1}{4}}^{/2}+7\frac{1}{8}=3\frac{2}{8}+7\frac{1}{8}=10\frac{3}{8}$